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integrate by substitution... x^3(6+5x^4)^7 .. my u=?
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u= (6+5x^4)?
yup
du= 20x^3?
yup again.
what about that 7th power?
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If you sub back in u and du your equation becomes|dw:1389927510861:dw|
u^7
yay! I know what im doing! thanks guys! sketch gets the best, tho.....
g(u)= u^7?
leads to-> 1/20*u^8/8 +c?
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Yes but you can't leave u in your answer so substitute back in.
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