What is the equation of a parabola with a vertex at (0, 0) and a focus at (0, 6).

Question

anonymous · Answer

@phi could you help me, I did this a few days ago but I need some brain refreshing

tkhunny · Answer

Vertex (0,0)
Focus (0,6)

You should recognize this information to be sufficient to suggest

$4py = x^{2}$, where $p$ is not yet known.

If you REALLY remember what will fairly likely be required of you an an exam, you should also notice that $p = 6$.

Almost an eyeball problem if you remember the general form and the complete meaning of the distance from the Vertex to the Focus.