Question

Please see my first comment for the problem ;w;

Answer 1

may i ask what grade this is for?

Answer 2

Find the value of
\[\tan (\alpha-\beta) \]
if
\[\cos \alpha =-\frac{ 3 }{ 5 }\]
\[\sin \beta=\frac{ 5 }{ 13 }\]
\[90degrees<\alpha<180degrees\]
\[90degrees<\beta<180degrees\]

Answer 3

just do cos^-1(-3/5) to find alpha, and sin^-1(5/13) to find beta. Then compute tan(alpha-beta)