Question

will give medal
Solve for x: 2|2x – 2| + 4 = 20
A. x = 5, x = –3
B. x = 5, x = –5
C. x = 3, x = –3
D. x = –5, x = 3

Answer 1

subtract 4 from both sides:
2|2x-2| = 16
divide by two on both sides:
|2x-2| = 8
now use casework and split the absolute value into 2 cases:
2x-2 = 8 or 2x-2 = -8
solving for both equations:
x = 5, x = -3
the answer is A

Answer 2

thank you so much!!

Answer 3

you're welcome

Answer 4

I have one more if you don't mind

Answer 5

ok

Answer 6

what is it

Answer 7

Solve for x: 3x – 2 > 5x + 10
A. x > 6
B. x < 6
C. x < –6
D. x > –6

Answer 8

add 2 to both sides:
3x > 5x + 12
subtract 5x from both sides:
-2x > 12
divide by two and switch the "greater than" to "less than":
x < -6
the answer is C

Answer 9

thank you so much!!

Answer 10

you're welcome