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Mathematics 19 Online
OpenStudy (sonyalee77):

weights, in pounds, of a group of student are as follows: 173 123 171 175 188 120 177 160 151 169 162 128 145 140 158 132 202 162 154 180 164 166 157 171 175 Determine the mean, standard deviation, and five-number summary for the data. a. Mean is 160.12; Standard deviation is 19.8. Five-number summary: min = 120, = 148, median = 162, = 174, max = 202 b. Mean is 162; Standard deviation is 19.8. Five-number summary: min = 120, = 148, median = 160.12, = 174, max = 202 c. Mean is 160.12; Standard deviation is 15.5. Five-number summary:

OpenStudy (sonyalee77):

@nubeer

OpenStudy (sonyalee77):

Please help

OpenStudy (sonyalee77):

@ganeshie8

OpenStudy (sonyalee77):

@Compassionate

OpenStudy (sonyalee77):

@wolfe8

OpenStudy (sonyalee77):

@skullpatrol r u going 2 help me?

OpenStudy (sonyalee77):

@Thatguy12310 can u help me?

OpenStudy (anonymous):

it is a tuff one but i guess

OpenStudy (sonyalee77):

Thanx

OpenStudy (sonyalee77):

Is it C?

OpenStudy (anonymous):

i think its b or c but im not sure

OpenStudy (anonymous):

tnx for medal

OpenStudy (anonymous):

its English but can you help me

OpenStudy (anonymous):

mean = add them up and divide by the number of data values median= half ar larger, half smaller max = largest min = smallest standard deviation = square root of sum of squares of differences between the values and the mean.

OpenStudy (anonymous):

A woman running for mayor makes a speech. She says, "A leader should be strong and true. Vote for freedom. Vote for patriotism. Vote for me!" What propaganda technique is the speaker using to win votes? Fear Glittering generalities Plain folks Transfer

OpenStudy (anonymous):

All that glitters is not gold.

OpenStudy (texaschic101):

The first part of your question is A. mean is 160.12, standard deviation is 19.8...etc. second one is glittering generalities

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