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If f(x) = x 2 + 1 and g(x) = 3x + 1, find g(20) + f(6).
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g(20) means put the value 20 in the place of g(x) to get the value
like g(20)= 3(20)+1=61
now put f(6) in f(x) and get the value
im confused
what are u confused in?
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whats the answer suppose to be....
is that \[f(x)=x^2+1\]
yes
final answer should be\[(6)^2+1+61=98\]
thanks
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