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Mathematics 9 Online
OpenStudy (anonymous):

csc-sin/cot^2=sin

OpenStudy (amoodarya):

\[\frac{ \csc x- \sin x }{ \cot ^2 x }=\sin x\] do you me an ?

OpenStudy (amoodarya):

or \[\csc x- \frac {\sin x}{\cot ^2 x} = \sin x\]

OpenStudy (anonymous):

My first step would be to change all of the csc's and cot's to terms of sin and cos. Then simplify like a normal complex fraction. If you need more assistance than this please show me what you got after the first step.

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