what is the solution of the equation?

Question

abb0t · Answer

B?

joshawad · Answer

what equation?

anonymous · Answer

sorry thats the right one! :)

ybarrap · Answer

$$
3^5\sqrt{(x+2)^3}+3=27\
\sqrt{(x+2)^3}+3=\cfrac{27-3}{3^5}\
(x+2)^3=\left (\cfrac{27-3}{3^5}ight )^2\
x+2=\sqrt[3]{\left (\cfrac{27-3}{3^5}ight )^2}\
x=\sqrt[3]{\left (\cfrac{27-3}{3^5}ight )^2}-2\
x=\sqrt[3]{\left (\cfrac{24}{3^5}ight )^2}-2\
$$

joshawad · Answer

yeah that's right

anonymous · Answer

ughhh Im sorry guys. i typed it in wrong again. im tired. here is the right equation I need help with. Sorry again. especially ybarrap!

anonymous · Answer

$$3\sqrt[5]{(x+2)^3}+3=27$$

ybarrap · Answer

$$
3\sqrt[5]{(x+2)}+3=27\
\sqrt[5]{(x+2)}=\cfrac{27-3}{3}\
(x+2)=\left (\cfrac{27-3}{3}ight )^5\
x=\left (\cfrac{27-3}{3}ight )^5-2\
x=\left (\cfrac{24}{3}ight )^5-2\
x=8^5-2\
=32,766
$$

anonymous · Answer

Im sorry @ybarrap last one i promise!

anonymous · Answer

wolframalpha.com will show u steps with answer like he did for you above