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OpenStudy (anonymous):
Identities... cos^2 x = cscxcosx/tanx + cotx
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OpenStudy (anonymous):
can u please recheck ur question
OpenStudy (anonymous):
cos^2x=\frac{cscx.cosx}{tanx+cotx} =\frac{\frac{1}{sinx}.cosx}{\frac{sinx}{cosx}+\frac{cosx}{sinx}} =\frac{\frac{cosx}{sinx}}{\frac{sin^2x+cos^2x}{sinx.cosx}}
OpenStudy (anonymous):
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