6. How many real number solutions does the equation have?

y = 2x² – 20x + 50

one solution
two solutions
no solutions
infinitely many solutions

Question

6.   How many real number solutions does the equation have?

y = 2x² – 20x + 50  


one solution
two solutions
no solutions
infinitely many solutions

solomonzelman · Answer

set it equal to zero (instead of y) and apply the quadratic formula.

anonymous · Answer

I don't get your formula

solomonzelman · Answer

or actually not a quadratic, factor it out after setting it equal to zero.

solomonzelman · Answer

$$\huge\color{blue}{  2x^2-20x+50=0 }$$$$\huge\color{blue}{  2(x^2-10x+25)=0 }$$$$\huge\color{blue}{  (x^2-10x+25)=0 }$$

factor

anonymous · Answer

your making it compilacting

solomonzelman · Answer

Look at my work in blue.

anonymous · Answer

still stuck

solomonzelman · Answer

can you factor out,$$\huge\color{green}{ x^2-10x+25= 0 }$$
( it's a perfect square )

solomonzelman · Answer

what 2 numbers add to get 10, and multiply to 25 ?

anonymous · Answer

Do you just want an answer?

shamil98 · Answer

it's probably from a quiz, since it is multiple choice.... 
anyways
GOFORMITTENS 2k14

anonymous · Answer

Because you don't want to answer any of @SolomonZelman 's questions.

anonymous · Answer

There is no solution because those terms can't add up.

anonymous · Answer

$$y=2\left( x ^{2} -10x+25\right)=2\left( x-5 \right)^{2}\ge 0 $$