Question

Help! Calculus

find the equation of the straight line tangent to the graph of the function f(x)=2x^2-7x+5 at the point (-4,65)

a) where is m?, where is b?

Answer 1

find f'(x) at x=-4 this is m.
eq. of line is y-65=m{x-(-4)}
then simplify.

Answer 2

when finding f'(x) at x=-4 do i jsut sub -4 into the original equation?

Answer 3

is it

Answer 4

f^1(x)=4x-7

Answer 5

f'(x)=4x-7
m at x=-4 is=4*-4-7=-16-7=-23
y-65=-23(x+4)