Question

help prove that tanx(tanx+cotx)=sec^2 of x ???

Answer 1

Have you considered multiplying with the Distributive Property on the left-hand side?

Answer 2

yeah. I got tan^2 of x +tanxcotx=sec^2 of x
I just don't know where to go from that point.

Answer 3

\(\tan(x) = \dfrac{1}{\cot(x)}\)

Answer 4

tan(x)cot(x)=1