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What is the equation of a line that passes through the point (0, -2) and has a slope of -3? y = -3 y = -3x - 2 y = -2x - 3 y = -2
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Use point-intercept form. y-y1=m(x-x1); using point (x1,y1) and slope m
so it would be y-(-2)=-3(x-0); now solve for y
y+2=-3x -2 -2 y=3x-2
y-(-2)=y+2
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