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factorise. (x + y)^2 + 8(x + y)
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\[(x + y)^2 + 8(x + y)= (x+y) (x+y +8) \]
@Danndann if you had $$\Huge a^2+8a$$ how would you factor it?
just yank out the (x+y)
@skullpatrol a(a + 8) ?
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Correct. Now let a = x+ y
$$\Huge (x + y)^2 + 8(x + y)$$ $$\Huge \text{Let } a= x+y.$$ $$\Huge \text{Then } (x + y)^2 + 8(x + y) = a^2+8a.$$
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