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Calculus1
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Solve for t: e^ln(0.6)t = 0.9
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e^x and ln(x) are inverse operations. As such e^ln(t) = t e^ln(0.6)t = 0.9 0.6t = 0.9
Thanks! That's what I thought it was, but wasn't sure. So, 1.5 is the answer?
yep. 0.9/0.6 = 1.5
Thank you!!!
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