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Mathematics 14 Online
OpenStudy (sarahc):

What is the solution set of....

OpenStudy (sarahc):

OpenStudy (anonymous):

x<-10, x>4

OpenStudy (sarahc):

Thank you!! could I give you a couple more questions?

OpenStudy (anonymous):

yes

OpenStudy (sarahc):

OpenStudy (anonymous):

Distribute the 5k^2 to all the elements.

OpenStudy (anonymous):

5k^2(2k^3) = (5*2)k^(2+3)

OpenStudy (sarahc):

ohh okay thanks

OpenStudy (anonymous):

Because only one answer has that first number, you should know what it is.

OpenStudy (anonymous):

Multiply the bases in this case, and add the exponents, if you didn't understand

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