Question

9c(c-11)+10(5c-3)=3c(c+5)+c(6c-3)-30
I got -49c=12c but I know that it's not right please help

Answer 1

I don't think so. There's either no answer or c=0

Answer 2

9c(c-11)+10(5c-3)=3c(c+5)+c(6c-3)-30
Well first you should distribute all the brackets in the equation by multiplying in whats inside.
9c-99c+50c-30 = 3c+15c+6c-3c-30
THEN, we just simplify, by combining all like terms!
-90c+50c-30=28c+6c-3c-30
-40c-30=31c-30
Subtract 31 from both sides.
-40c-30-31c=31c-30-31c
Add positive 30 to both sides.
-40c-30-31c+30=-30+30
-71c=0
Divide -71.
C = 0

Answer 3

OMG thank you so much!