Question

please check my answers
will award medal and fan

Answer 1

1st one u got the wron ans

Answer 2

Can you help me

Answer 3

very very close on the 2nd one but still wrong :( the expression is right but one of the inequality is wrong.

Answer 4

p^2-4p-32=(p+4)*(p___) fill in the blank there plz? :)

Answer 5

wrong on the 3rd one too sorry :(

Answer 6

I don't understand can you help me ?

Answer 7

i will do the top on the 3rd eqn for u:
\[z ^{2}*(z ^{2}+3z+2)=z ^{2}*(z+2)*(z+1)\]

plz group the bottom half of the eqn

Answer 8

HI :D

Answer 9

for the first question, please group the top half like this:
p^2-4p-32=(p+4)*(p___)

Answer 10

p^2-4p-32= ( p+4)*(p-4) ?

Answer 11

Please check ur math again because +4*(-4) is -16 and it should be -32

Answer 12

p^2-4p-32= ( p + 4 ) * ( p - 8 )

Answer 13

bingo...put that back in the eqn n the answer for 1st question should be....

Answer 14

b ?

Answer 15

that is correct :)

for the second question, did u see what I said earlier?
"very very close on the 2nd one but still wrong :( the expression is right but one of the inequality is wrong."

so check the inequality plz

Answer 16

would it be c

Answer 17

correct again :) do u know what mistake u made there?

Answer 18

yes i see what i did haha

Answer 19

what about the third any idea?

Answer 20

I did half of it for u already :P
"
i will do the top on the 3rd eqn for u:
z2∗(z2+3z+2)=z2∗(z+2)∗(z+1)


plz group the bottom half of the eqn"

Answer 21

i don't know how haha sorry

Answer 22

do u follow what I did w the expression above? the bottom one u can group them the same way....

Answer 23

z+1*(z2+3z)

Answer 24

(z+1)*z*(z+3) okay?

Answer 25

okay i understand sorry

Answer 26

put the top n bottom together, u will get....

Answer 27

z2∗(z2+3z+2)=z2∗(z+2)∗(z+1) / (z+1)*z*(z+3)

Answer 28

eliminating same express above n below....

Answer 29

same expressions or terms