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Mathematics 19 Online
OpenStudy (ashleyisakitty):

Find the value of x in this circle

OpenStudy (ashleyisakitty):

OpenStudy (raden):

x is radius of that circle, so just use pythagorean theorem again

OpenStudy (ashleyisakitty):

22^2+8^2=x^2?

OpenStudy (raden):

22/2, first

OpenStudy (ashleyisakitty):

so 2√137=23.4 which is the answer

OpenStudy (ashleyisakitty):

right?

OpenStudy (raden):

that should be 11^2 + 8^2 = x^2

OpenStudy (ashleyisakitty):

therefore the answer is 13.6

OpenStudy (raden):

yes, that's right

OpenStudy (ashleyisakitty):

many thanks :)

OpenStudy (raden):

you're welcome

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