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binomial theorem (2x+4)^3
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(2x+4)^3=(2x)^3 * 4^0+(2x)^2 * 4^1 + (2x)^1 * 4^2+ (2x)^0 * 4^3
how is this exactly?
This is using the binomial theorem (left out the factorial terms): http://en.wikipedia.org/wiki/Binomial_theorem (2x+4)^3=(3C0)*(2x)^3 * 4^0+(3C1)*(2x)^2 * 4^1 + (3C2)*(2x)^1 * 4^2+ (3C3)*(2x)^0 * 4^3=8 x^3+48 x^2+96 x+64
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