Question

Did I do this right?

Put the function P=6(2.3)^t into P=Poe^kt format.

Po=6
2.3^t = e^kt
ln(2.3)^t = lne^kt
ln(2.3)^t=kt
tln(2.3)=kt
ln(2.3)=k
k=0.83

P=6e^0.83t

is that right? :)

Answer 1

If e^0.83 = 2.3, then you did it right.

Answer 2

oh okie :) yay!! thank you!! :D