If arcAC=48, what is mBD?
Are we assuming that AC is congruent to AD? Is there any additional information?
that AB is perpendicular to CD
Alright. Thanks. That helps a lot. I'm breaking out my trusty pen and paper.
My pencil broke. This is an emergency. I require a pencil sharpener. BRB as I frantically search.
okay hurry back T-T
@ganeshie8 DON'T YOU SNIPE ME AGAIN
il give a hint maybe : mBD = mBC
:)
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Am i supposed to find wht BD is through using the arc 48? I really dont know.
vague hints arent really helpful...
ok. do u know that thoerem that states an inscribed angles is half the measure of its intercepted arc?
|dw:1390276506003:dw|
with that thoerem, u will find this |dw:1390276593528:dw|
and using that the sum of a trinalge = 180. so 90+24+x=180 and x=66 |dw:1390276703687:dw| and yea, its that conjecture thing
and finally since arc BD is the intercepted arc of inscribed angle BAD. arc BD=66x2 or132
Okay guys I'm back. @Ashleyisakitty ?
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