Medals will be given need help with problems, have the answers already just need to work them out. 1.x^2 + 20x + 99 2.n^2-13n+ 40 3. x^2-8x-20 5. x^2 + 7xy - 44y^2 6. 2x^2 + 7x +6
are u looking for the factors?
no just to work the problem out i already have the answer
1.1*99=99 11*9=99 11+9=20 2.1*40=40 -8*-5=40 -8+(-5)=-13 3.1*-20=-20 -10+2=-8 -10*2=-20 4.1*-44=-44 11-4=7 11*-4=-44 5.2*6=12 4+3=7 4*3=12
What's the name of this lesson? Like, is it Radical expressions or sumthin like dat?
@surjithayer can you please number them and space them ? its confusing
only three rows for every problem. i have given hint only to make factors.
are you sure this is right ? i have the answers
yes ,absolutely correct.
Do your answers match his?
do you have #6 ?
now i figured 4 th is missing. so consider 4th as 5th and 5 as 6th.
@Goku-Kai he didnt give me the answers he just showed the work i dont need the answers!!!
@bettylee No, I thought you said you have the answers already and he worked through the problem so I didn't know if y'all answers matched up that's all. I'm sorry...
x^2+7xy-44y^2 =x^2+(11-4)xy-44y^2 =x^2+11xy-4xy-44y^2 =x(x+11y)-4y(x+11y) =(x+11y)(x-4y)
no i didnt say it rudely lol i was just saying i dont want anyone giving me the answers because i have them i justb really need to work the problem out loll
@surjithayer thank you so much really helpful i have some more if you want to help if not then ill just post them
Oh lol, It's hard to comprehend the emotions of people by reading text lol. But I gotchu, it's all love.
lollll its okay it can be sometimes i looked back at the message and it does sound rude but it wasnt lmaooo. all love!!!
when the product of co-efficient of x^2 and constant term is positive,then break the coefficient of x in two parts such that their product is same . when product is negative then coefficient of x=larger -some number such their product is same and difference is coefficient of x.
okay i understand thank you for explaining that for me really you were a big help!!! @surjithayer
yw
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