Question

If f(x)=sin^2(3-x), then what is the exact value of f'(3-2pi/3)?

Answer 1

\[
f'(x)=-2 \sin (3-x) \cos (3-x)
\]
Can you finish it now?

Answer 2

\[

f'\left(3-\frac{2 \pi }{3}\right)=\frac{\sqrt{3}}{2}
\]

Answer 3

Ask me if you still do not understand it?