Question

Given: rectangle ABCD is similar to rectangle ZBXY.


If BA=8, BC=12 and the perimeter of rectangle BXYZ is 20, find BX.


A. 3

B. 4

C. 5

D. 6

Answer 1

perimeter of larger rectangle is 40 which is twice the perimeter of smaller rectangle
because they are similar all sides are proportional

larger sides are twice as long as smaller sides
BC = 12 thus BX = 6

Answer 2

Perimeter of ABCD = 2(8) + 12(2)

Perimeter of ABCD =16 + 24 = 40

BA / BX = ABCD / BXYZ

8 / BX = 40 / 20

8 / BX = 4/2

8 (2) = 4 BX

16 = 4BX

BX = 4

Answer 3

how did you end up with 8/BX=4/2? @Nurali

Answer 4

@Nurali
BC corresponds with BX not BA

Answer 5

how? how do you know which one corresponds with one one

Answer 6

look at length and width of each rectangle

lets say length is longer side
length corresponds to length
width corresponds to width

Answer 7

are you positive it is 6?

Answer 8

lol yes