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(x)/b-3 = bx-6 Can someone take me step by step on how to do this? (solve for x)
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You can use b = 2 and x = 2 Or x = -2 and b = -2 2/2 = 1 1-3 = -2 b*x = 2*2 4-6 -2 = -2
So the answer is 2 ?
b = 2 x = 2 OR x = -2 and b = -2 I'm assuming you know that 2 negatives cancel out and make a positive xD
That's not correct
(x)/b-3 = bx-6 x=(b-3)(bx-6) x=b^2x-6b-3bx+18 x-b^2x+3bx=-6b+18 x(1-b^2+3b)=-6b+18 x=(-6b+18)/(1-b^2+3b)
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0_0
o.o ohh they're polynomials..? -sigh-
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