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Mathematics 19 Online
OpenStudy (anonymous):

Please help me solve the following logarithmic equation. Thank you :)

OpenStudy (anonymous):

log[base6] (x+3) + log[base6] (x-2) =1

OpenStudy (anonymous):

you're welcome :)

OpenStudy (ikram002p):

OpenStudy (anonymous):

See @ikram002p , I tried it that way and I didn't get the correct answer which is x=3

OpenStudy (ikram002p):

humm how do u know that the correct is x=3 ?

OpenStudy (anonymous):

I have problems with logarithms, are you in connections?

OpenStudy (ikram002p):

ohhh sry i made a typo ill do it again for u

OpenStudy (anonymous):

I am not, sorry @usernae. @ikram002p answers given said so :P

OpenStudy (anonymous):

okay! well can someone help me with a problem

OpenStudy (anonymous):

I can try.

OpenStudy (anonymous):

The half-life of a certain radioactive material is 42 days. An initial amount of the material has a mass of 49kg. Write an exponential function that models the decay of this material. Find out how much radioactive material remains after 8 days. Round your answer to the nearest thousandth.

OpenStudy (ikram002p):

@lovethecreation ur right sry its 3 :)

OpenStudy (anonymous):

Thank you @ikram002p , can I ask one more question please?

OpenStudy (anonymous):

I can try to answer your quesion, so go ahead

OpenStudy (ikram002p):

ok ill try

OpenStudy (anonymous):

thank you! I appreciate the help :) log[base5] (7x+1) - log[base5] (x-1)=2

OpenStudy (anonymous):

@usernae i'm working on your question. It's easy. Try it by using the exponential decay/ half life formula.

OpenStudy (anonymous):

alright! Thank you!

OpenStudy (anonymous):

alright! Thank you!

OpenStudy (anonymous):

@usernm You're welcome. let me know If you have any trouble although my explanation is pretty straight forward.

OpenStudy (anonymous):

@ikram002p how you doing with the question?

OpenStudy (ikram002p):

ima slp gn :o

OpenStudy (ikram002p):

OpenStudy (anonymous):

Perfect, thank you very much @ikram002p . Sleep well :)

OpenStudy (anonymous):

@usernae you good?

OpenStudy (ikram002p):

tyyy :D wish me luck i had final exam tomoro XD

OpenStudy (ikram002p):

gud luck for u :o

OpenStudy (anonymous):

Good luck! I'm sure you'll do fantastic :) Thank you!

OpenStudy (ikram002p):

ur wlc! anytime ^_^

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