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How to solve this log x - log 12 = 3
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\[\huge\color{blue}{ \log(x)-\log(b)=\log(x/b) } \]
\[\color{blue}{ \log(x)-\log(12)=\log(x/12) } \]\[So,~~~~~~~~~~\color{blue}{ \log(x/12)=3 } \]\[\color{blue}{ \log(x/12)=(\log_33) \times 3 } \]\[\color{blue}{ \log(x/12)=3(\log_33) } \]\[\color{blue}{ \log(x/12)=(\log_33^3) } \]\[\color{blue}{ \log(x/12)=\log_327 } \]\[\color{blue}{ \log(x/12)=\frac{\log_{10}27}{\log_{10}3} } \]can you do it from here?
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