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Mathematics 20 Online
OpenStudy (anonymous):

help

OpenStudy (anonymous):

OpenStudy (anonymous):

@RadEn

OpenStudy (raden):

if x real, then it is A

OpenStudy (anonymous):

OpenStudy (anonymous):

thanx how about this one

OpenStudy (raden):

sqrt(x) < 16 first, squared both sides get x < 16^2 or x < 256 then x must be positive, in other words 0 ≤ x therefore, the solution is 0 ≤ x < 256

OpenStudy (anonymous):

thanx

OpenStudy (anonymous):

I have 6 more could you also help with that

OpenStudy (anonymous):

@RadEn

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