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Find the vertex and axis of symmetry of the graph of the function: f(x)=2x^2+8x
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Put the equation into this form: f(x)=2(x^2+4x) Then complete the square.
how do u complete the square?
Take half the coefficient of x and square it.
y+4=2x^+4x+4
y+8=2(x^2+4x+4)
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so i solve that to find the vertex?
Put it into this form: y=(x-h)^2+k (h,k) is the vertex
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