Question

Find the second term in this sequence: tn= (6-n)^2

Answer 1

$$
\Large
t_n=(6-n)^2
$$
1st term is \(t_0\), second term is \(t_1\):
$$
t_1=(6-1)^2=5^2=25
$$
Make sense?

Answer 2

yes thankyou!!

Answer 3

its not clear if n starts at n=1 or n = 0

Answer 4

Typically, indices start at 0, unless it's forbidden, as in 1/n.

Answer 5

@ybarrap no, it doesn't show to me. \[\text{No, it doesn't show}\]

Answer 6

If you can't see the LaTex, follow these instructions @Loser66 - http://openstudy.com/study#/updates/52de57e0e4b003c643a10b24