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Mathematics
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. Let f(x) = x2 + 2, 0 ≤ x ≤ 1. Find the volumes of the solids formed when (d) the region enclosed by the y-axis, y = f(x) and y = 3 is rotated around the x-axis.
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use disks
dV = [pi*3^2 - pi*(x^2+2)^2]*dx
take the integral
The volume is 182pi/15 ??
wolfram says 52pi/15 http://www.wolframalpha.com/input/?i=int_0%5E1++%5Bpi*3%5E2+-+pi*%28x%5E2%2B2%29%5E2%5D+dx
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Would I not use the washer method: The outer radius being y=3 and the inner radius being x^2+2 so when this is plugged in to the formula I get 38Pi/3
sorry yes it is 52Pi/5 Thank you!
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