What is the equation in standard form of the line which passes through (-2, -3) and has a slope of 1/2 ?
2x + y = 4
2x - y = 4
x + 2y = 4
x - 2y = 4

Question

What is the equation in standard form of the line which passes through (-2, -3) and has a slope of 1/2 ? 
   2x + y = 4 
 2x - y = 4 
 x + 2y = 4 
 x - 2y = 4

anonymous · Answer

help please

anonymous · Answer

@ybarrap can you please help me

ybarrap · Answer

you have the slope and so we just need to find the y-intercept:

y=mx+b, where m is the slope (1/2) an b is the y-intercept

Take the point (-2,-3) and just plug into y=mx+b to find b:

-3=(1/2) * (-2) + b

b=-3 +1=-2

So, y = (1/2) x  - 2
 
Multiply both sides by 2:

2y - x = -4

Multiply both sides by -1:

x - 2y = 4

That's it.

anonymous · Answer

thank you so much!! (: