OK so pre-calc question:

solve the triangle A=50, b=13, c= 6

Am I doing this correctly and if I am can you guide me to the next process, however if I've goofed up help me to the right path

cos A = b^2 + c^2 - a^2 / 2bc
cos 50 = 13^2 + 6^2 - a^2 / 2(13)(6)
cos 50 = 205 - a^2 / 156
?????

Question

OK so pre-calc question:

solve the triangle A=50, b=13, c= 6

Am I doing this correctly and if I am can you guide me to the next process, however if I've goofed up help me to the right path

cos A = b^2 + c^2 - a^2 / 2bc
cos 50 = 13^2 + 6^2 - a^2 / 2(13)(6) 
cos 50 =  205 - a^2 / 156
?????

anonymous · Answer

You are almost there.
Next step is to set the equation 
a^2/156=205-cos 50
then you get
a^2=205-cos 50 times 156

From this point, I use calculator to find a.

Good Luck