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1,700 kg car coasts down a hill starting from rest and decreases its height by 22 m over a distance of 110 m of travel. How fast will it be going at the end of the hill, if friction has no effect in slowing its motion? I have the answer I just need to know how to work it out the answer is 21m/s I just need help explaining my answer please
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use one of the equations of motion, v = u + at i believe.
so how would you do that
The gain in kinetic energy, (1/2)m v^2 = the loss in potential energy, m g h. Solve for v. Height crucial, distance irrelevant.
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