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Mathematics 16 Online
OpenStudy (anonymous):

The length of a rectangle is twice the width. The perimeter is 85 cm more than the width. Make a diagram and find the rectangles dimensions. P=2l+2w

OpenStudy (lucaz):

the perimeter is the sum of the sides, a rectangle has 4 sides, 2 widths and 2 lenghts

OpenStudy (lucaz):

the length is twice the width, length = 2*width

OpenStudy (lucaz):

perimeter P=2*length+2*width P=2*(2*width)+2width

OpenStudy (lucaz):

solve the equation for w and go back to length = 2*w to find it's value

OpenStudy (anonymous):

What's the equation

OpenStudy (anonymous):

Is it w+85=2l+2w

OpenStudy (lucaz):

P=2*(2*width)+2width solve this equation to find the width

OpenStudy (anonymous):

So 85=5w and divide and get 17 so length equals 17

OpenStudy (anonymous):

?

OpenStudy (lucaz):

it seems we have a some decimals, do you have the answer?

OpenStudy (lucaz):

just to check

OpenStudy (anonymous):

85/5 is 17

OpenStudy (lucaz):

but it is not 5, it's 6, w = 85/6

OpenStudy (lucaz):

2*2w+2w = 4w+2w = 6w

OpenStudy (lucaz):

85/6 is approx. 14.16, the witdh is 14.16, the length is twice the witdh, 2*14.16 = 28.32 P = 2l+2w 85 = 28.32*2 + 14.16*2 = appox. 84.96, almost 85..

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