Ask
your own question, for FREE!
Mathematics
8 Online
OpenStudy (anonymous):
The length of a rectangle is twice the width. The perimeter is 85 cm more than the width. Make a diagram and find the rectangles dimensions. P=2l+2w
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lucaz):
the perimeter is the sum of the sides, a rectangle has 4 sides, 2 widths and 2 lenghts
OpenStudy (lucaz):
the length is twice the width, length = 2*width
OpenStudy (lucaz):
perimeter P=2*length+2*width
P=2*(2*width)+2width
OpenStudy (lucaz):
solve the equation for w and go back to length = 2*w to find it's value
OpenStudy (anonymous):
What's the equation
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Is it w+85=2l+2w
OpenStudy (lucaz):
P=2*(2*width)+2width
solve this equation to find the width
OpenStudy (anonymous):
So 85=5w and divide and get 17 so length equals 17
OpenStudy (anonymous):
?
OpenStudy (lucaz):
it seems we have a some decimals, do you have the answer?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lucaz):
just to check
OpenStudy (anonymous):
85/5 is 17
OpenStudy (lucaz):
but it is not 5, it's 6, w = 85/6
OpenStudy (lucaz):
2*2w+2w = 4w+2w = 6w
OpenStudy (lucaz):
85/6 is approx. 14.16, the witdh is 14.16, the length is twice the witdh,
2*14.16 = 28.32
P = 2l+2w
85 = 28.32*2 + 14.16*2 = appox. 84.96, almost 85..
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!