Question

A long jump shot is released 1.7 m above the ground, 5.92 m from the base of the basket, which is 3.05 m high. For launch angles of 30° and 60°, find the speed needed to make the basket.

Answer 1

You will need initial velocities

u = V cos @
v = V sin @

the height
h = 1.7 + v t - (1/2) (9.8) t^2

the horizontal distance

s = ut

and you have to combine these to make a basket. Try a graph at least to understand what the trajectories look like, if not to get exact V.