Calculus1
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OpenStudy (anonymous):
Lim x-> 0 , 6x^2 (cot x)(csc2x)
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OpenStudy (anonymous):
I have it to 6x^2 (cos x/sin x)(1/sin2x)
OpenStudy (superdavesuper):
then using the formula sin2A=2sinAcosA to simplify further...
OpenStudy (anonymous):
Ok
OpenStudy (anonymous):
Then what?
OpenStudy (superdavesuper):
show me what u get so far plz? :)
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OpenStudy (anonymous):
Lim x -> 0 , 6x^2(cos x/sin x)(1/2sin x cos x)
OpenStudy (superdavesuper):
simplify by canceling n regrouping terms above n below the / sign plz
OpenStudy (anonymous):
Cos x = 1 not sure what do with the rest
OpenStudy (superdavesuper):
nope, ok i will write it out...
OpenStudy (anonymous):
Sorry this has really been frustrating me
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OpenStudy (superdavesuper):
6x^2*(cosx/sinx)*(1/2sinxcox) so far so good?
OpenStudy (superdavesuper):
just be patience - u will work it out! :)
OpenStudy (anonymous):
Thanks
OpenStudy (superdavesuper):
Welcome :) Notice how u can cancel the cosx term and group the sinx term together in the eqn?
OpenStudy (anonymous):
Ok so does it become 1/3sin x
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OpenStudy (superdavesuper):
nope....u missed some terms there. remember sinx*sinx=(sinx)^2
OpenStudy (anonymous):
2 sin x^2
OpenStudy (superdavesuper):
It should be 2* x^2/(sinx)^2....plz check n make sure u get the same result here
OpenStudy (anonymous):
Where did the 2x^2 come from on top
OpenStudy (superdavesuper):
U said it urself "I have it to 6x^2 (cos x/sin x)(1/sin2x)" scroll up if u dont believe me lol
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OpenStudy (anonymous):
I do lol just still confused
OpenStudy (superdavesuper):
take a moment n read everything once more....next step will be a leap :O
OpenStudy (anonymous):
Ok so right now I have 6x^2(1/sin x)(1/2sin x)
OpenStudy (superdavesuper):
yup yup very good so 6/2=3 and then re-group so that u got the following:
3*(x/sinx)*(x/sinx) <- plz make sure u understand how i get here
OpenStudy (anonymous):
What happened to the x^2
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OpenStudy (superdavesuper):
it becomes the (x/...) and (x/...)
OpenStudy (anonymous):
Thought so. Thanks for being patient with me a putting up with me.
OpenStudy (anonymous):
So the answer is 3
OpenStudy (superdavesuper):
Bingo, good job! :)
OpenStudy (superdavesuper):
U are welcome