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how to integrate 7^2x. is it ( 7^2x ) / log7 ?
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\[ \frac {7^{2 x}} {2 \ln 7 } \]
so the integral of 7^5x is ( 7^5x ) / ( 5 log7 ) ?
(2 x)' = 2 you have to divide by 2
Yes
thx!
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