Question

4. simplify the complex fraction
n-4
_____
n^2-2n-15
______
n+1
____
n+3

A. n-4/(n-3)(n+1)
B. n-4/(n-5)(n+4)
C. n-4/(n-5)(n+1)
D. (n-4)(n+3)/(n-5)(n+1)

Answer 1

I think its C,

Answer 2

okay lol how did you get that ?

Answer 3

Because you would factor the n^2 - 2n - 15
I used 3, so n^2 - 2n - 15 = (n+3)(n-5)

So now you have: n-4/(n+3)(n-5)(n+1)(n+3)

Combine their exponent (add them),

(n+3)^-1-1 (n-4)/(n-5)(n+1)

(n-4)(n+3)^-2 /(n-5)(n+1)

n-4/(n-5)(n+1)

Answer 4

oh okay lol thank you :)

Answer 5

>.> might wanna check :3