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what is an equation of the line, in point slope form, that passes through the given point and has the give slope? point: (7,3); slope: 4/7 y-3=4/7(x-7) y-7=4/7(x-3) y-3=4/7(x+7) y-3=-4/7(x-7)
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y-y1=m(x-x1) y-3=(4/7)(x-7)
where x1 and y1 refer to the coordiantes provided to us and m is the gradient (slope)
that's right...y-y1=m(x-x1)...... see I can never find the stuff that I did 3 months ago in my book. its ridiculous. thank you for helping :)
no worries :)
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