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Mathematics 22 Online
OpenStudy (anonymous):

Can someone check my work ? [ sin(x)*tan(x) ]/ cos(x) =[sin(x)*sin(x)/cos(x)]/ cos(x) =[sin^2(x)/cos(x)]/cos(x) =[1-cos^2(x)] /cos(x) and I'm stuck here !

OpenStudy (loser66):

from line 3 , = sin^2/cos^2 = tan^2

OpenStudy (anonymous):

OpenStudy (anonymous):

Oh now I see it !

OpenStudy (anonymous):

Thank you both so much !

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