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Mathematics
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(2x³y²)-² (-̅x̅̅̅²̅y̅^̅5̅) ̅̅̅
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@nikato
= 2^(-2) * x^(-6) * y^(-4) / (-x^2 * y^5) = 1 / (2^2 * x^6 * y^4 * -x^2 * y^5) = -1 / (4 * x^8 * y^9) = -1/(4x^8y^9)
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