Question

Juniors and seniors at a local school were surveyed to see if they were left-handed or right-handed. The data is displayed in the table below.

Junior Senior
Left-handed 36 14
Right-handed 44 106


If a student is chosen at random from this group, what are the chances of choosing a student who is a left-handed senior?
@Mathbreaker

Answer 1

If you draw a tree diagram, you get the probabilities of each event happening. Now in this case, (14/200)*(120/200) is the probability of both of the events happening, considering first criteria to be left handed, which is 14 out of 200 people, and the second being senior, which is 120 out of 200.

Answer 2

you simplify that and you get 3/5 then what do you do? @Mathbreaker

Answer 3

uhh @Mathbreaker you there?

Answer 4

That's the answer..i think

Answer 5

its not in the options :/

Answer 6

you get 42/1000
which you simplify to get 21/500. Perhaps this is in the options? :/
If not then please tell me the options. My probability is a bit rusty :P

Answer 7

7%

18%

22%

53%

Answer 8

Omg i was overcomplicating such a simple issue.
As the basic value is already given, with the number, which is 14, you can simply divide that by 200 to get the answer.
Which is 7%
sorry. I feel stupid now :p

Answer 9

dont worry its just a feeling otherwise your smart! :)

Answer 10

Hehe thanks ;)
all the best man :)

Answer 11

This is correct!! Ty!! (Just took teh test)