Question

Write the equation of the line that is parallel to the line y = -3x + 12 and passes through the point (-1, 6).

y = one thirdx + 7

y = -3x + 3

y = one thirdx + 3

y = -3x + 7

Answer 1

when two line are parallel. their slopes are equal, now you have

y = -3x + 12 here the slope is -3 now the slope of the required line is also -3

now you have slope = m = -3 and point = (-1,6)

use the following formula to find the equation

y-y1 = m(x-x1) here m = -3 and x1 = -1 and y1 = 6

do it now