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Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2). y = -one thirdx - 6 y = -one thirdx - 14 y = 3x - 6 y = 3x - 14
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(1) Find the slope of the given line. (2) Substitute that slope and the coordinates of the given point into the point-slope formula for the equation of a straight line: y-y0 = m(x-x0). (3) Solve the resulting equation for y.
i would believe that it is the third choice
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