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OpenStudy (anonymous):
b(b^-8)^-3
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OpenStudy (cggurumanjunath):
go through above link.
OpenStudy (agent0smith):
b(b^-8)^-3 = b*b^(-8*-3) = ...?
OpenStudy (anonymous):
so would it be 1 over b^-24?
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OpenStudy (agent0smith):
It's easier to just multiply the exponents as i showed, same result with less work. b*b^(-8*-3) =
OpenStudy (cggurumanjunath):
b^25 is the final answer @9000872
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