The length of a rectangle is 2 more than three times the width. The area of the rectangle is 161 square inches. What are the dimensions of the rectangle?

If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?

2x2 + 3x - 161 = 0
3x2 + 2x - 161 = 0
6x2 - 161 = 0

does anybody knows the answer? :O
am struggling with this question... :/

Question

The length of a rectangle is 2 more than three times the width. The area of the rectangle is 161 square inches. What are the dimensions of the rectangle? 

If x = the width of the rectangle, which of the following equations is used in the process of solving this problem? 


2x2 + 3x - 161 = 0
3x2 + 2x - 161 = 0
6x2 - 161 = 0

does anybody knows the answer? :O
am struggling with this question... :/

cggurumanjunath · Answer

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cggurumanjunath · Answer

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anonymous · Answer

it wont let me... it  says that this page does not exist :/

cggurumanjunath · Answer

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