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Mathematics 23 Online
OpenStudy (anonymous):

Find the perimeter of a rectangular object which has a length of square root of 180 feet and a width of square root of 125 feet. Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form. What type of object in your home or school might this be?

OpenStudy (anonymous):

OpenStudy (anonymous):

Sq rt of 280 is 13.4 ft. and the sq rt of 125 is 11.18 ft. This means that the perimeter is 49.16 ft. I just used my calculator to find the sq rt and the perimeter. Possible a table or a wall.

OpenStudy (anonymous):

it may be a tv screen

OpenStudy (studygurl14):

P = 2L + 2W P = 2(sqrt180) + 2(sqrt125) P = 2sqrt(2*2*45) + 2sqrt(5*5*5)

OpenStudy (anonymous):

She said that it was feet. How could it be a T.V. If it was, then I want that T.V.

OpenStudy (anonymous):

yeah right hahah!! sorry

OpenStudy (studygurl14):

P = 2(2)sqrt(45) + 2(5)sqrt(5)

OpenStudy (anonymous):

@HannahLuv, you're going to need to combine the answers on here to get a complete one.

OpenStudy (anonymous):

yes thanks everyone! :)

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