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OpenStudy (anonymous):
The function y=log2^x is a logarithmic function true or false
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OpenStudy (anonymous):
It is true, to me...
OpenStudy (anonymous):
y=log 2^x or y=x log 2 log 2 is constant. y=kx ,where k is a constant. Now you can write the answer yourself.
OpenStudy (anonymous):
Thank you!
OpenStudy (anonymous):
yw.
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